The limiting reagent is sodium sulfate.
The percent yield calculated is 82.5 %.
666.808 is the theoretical yield.
666.808 x .825 = 550.1166 g
666.808 g is the mass of calcium sulfate at 100 % yield.
550.1166 g is the mass of calcium sulfate at 82.5 % yield.
CaNO3 + NaSO4 --> CaSO4 + 2NaNO2
CaNO3= 102.09 g
NaSO4= 119.06 g
NaNO3= 85 g
CaSO4= 136.15 g
500g CaNO3 x 1 mole/ 102.09g = 4.8976 mol CaNO3
500g NaSO4 x 1 mol/ 119.06g = 4.2 mol NaSO4
4.8976 mol CaNO3 x 1 mol NaSO4/ 1 mol CaNO3 = 4.8976 mol NaSO4
4.8976 mol CaNO3 x 1 mol CaSO4/ 1 mol CaNO3 = 4.8976 mol CaSO4
4.8976 mol CaSO4 x 136.15g/ 1 mol = 666.808 gt CaSo4